.isalpha () with spaces does not work in Python 3x

.isalpha() only returns True if all the characters in the string they are alphabetic and there is at least one character, otherwise returns False .

If the check also has to accept blanks, you can use something like this:

if all(x.isalpha() or x.isspace() for x in equipo):

This expression will be True for strings that contain spaces and alphabetic characters. However, if you need to also accept numeric characters (for example Shalke 04 ), you must modify the expression to allow them:

if all(x.isalnum() or x.isspace() for x in equipo):

isAlpha() returns true if all the characters are alphabetic and there is at least 1 character. Returns false because space is not an alphabetic character.

The simplest would be to replace the spaces with empty and then use isalpha() :

equipo.replace(" ", "").isalpha()

Another way to detect that you have only letters (and spaces) you can use Regex :

import re
while True:
    equipo = input("\n¿Con que equipo te gustaria jugar? Escribelo aqui: ")

    pattern = re.compile("^[A-Z ]+$")

    if pattern.match(equipo.upper()):
        if equipo == "Barcelona":
            print ("Buena eleccion!")
            break
        if equipo == "Real Madrid":
    . . . 

The regular expression ^[A-Z ]+ supports letters and spaces. You can add Numbers by:

  

^[A-Z0-9 ]+$

Note: In the checks that you make of "equipo == "Barcelona":" you run the risk that put "barcelona" and no longer work. For that, put both a upper() or lower() such that:

equipo.lower() == "Barcelona".lower():