Problem in a C entry

Question

Problem in a C entry

Navigation

#1 by (3 votes)

1

Someone could explain or say, Why does not the code enter? If 0 comes out, it only ends.

#include <stdio.h>  
#include <stdlib.h>
#include "dibujos.h"
#include <time.h>  
int main(){
    char pal_1 [12] = "hogar";          
    char let;                                  
    int vidas = 0;                             
    srand(time(NULL));

    system("cls");
    TituloJuego();
    SinAhorcado();
    printf("\n\n");
    system("pause");
    int pal = rand() % 10;                    
    printf("%d" , pal);
    if(pal = 0){
        while (vidas !=0){
        system("cls");
        TituloJuego();
        SinAhorcado();
        printf("\n\n");
        printf("Palabra secreta:_ _ _ _ _ \n");
        printf("Ingrese una letra: ");
        scanf("%c", &let);
        if( let = "b" || "B" || "c" || "C" || "d" || "D" || "e" || "E" ||
            "f" || "F" || "i" || "I" || "j" || "J" || "k" || "K" || "l" ||
            "L" || "m" || "M" || "n" || "N" || "p" || "P" || "q" || "Q" ||
            "s" || "S" || "t" || "T" || "u" || "U" || "v" || "V" || "w" || 
            "W" || "x" || "X" || "y" || "Y" || "z" || "Z"
        ){
            system("cls");
            TituloJuego();
            Cabeza();
            printf("\n\n");
            system("pause");
            printf("hola");
        }
    }   
}

c

asked by Thasdjl 26.09.2016 в 23:30

source

1 answer

list data in a partial view by passing it from a modal window what is it used for #ifdef_MSDOS_ in c ++?

score 3 · Answer 1

Let's start with the basics:

The comparisons in C are made in the following way:

if (izq <operador> der) { /* ... */ }
O:
if (true||false) { /* ... */ }

Where:

izq : It is the operand in the left hand, a variable or a value to be compared.

<operador> : Can be any of the comparison operators:

<= : Less than or equal to what
< : Less than
== : Same as
!= : Different from
> : Greater what
>= : Greater than or equal to what

der : Value or variable that we expect to have (or not) on the left side.

What you are currently comparing:

if (let = "string" || "otro string")
Y:
if (pal = 0)

It should cause a compile-time error, since let is type char and not char* , although I'm not very good with C, so I can not comment on it, the chars are enclosed within single quotes ( ' ), and not double ( " ) , currently, if compiled, but it turns out that it evaluates any string of characters, so it will always be true.

On the subject of assignment in a comparison, it is badly raised, by doing:

if (pal = 0)

You are assigning zero to pal , which in the end translates to the following comparison:

if (0)

And in C, 0 means false.

Another thing, scanf("%c", /* ... */); is waiting for a type char , so you can not compare let with a char array, instead, you can compare as follows:

if ((let >= 'b' && let <= 'z') || (let >= 'B' && let <= 'Z')) {
    /* ... */ 
}

Ah! The vidas , I believe ... will always be zero, so it will never enter the cycle while , and if it is different from zero, there is no method or action that allows the change of value of that variable.

Then, leaving all the code:

int main(){
    char pal_1 [12] = "hogar";          
    char let;                                  
    int vidas = 5;                             
    srand(time(NULL));

    system("clear");

    int pal = rand() % 10;                    
    printf("%d\n" , pal);
    if(pal == 0) {
        while (vidas != 0) {
            system("clear");
            printf("Palabra secreta:_ _ _ _ _ \n");
            printf("Ingrese una letra: ");
            scanf("%c", &let);

            if((let >= 'b' && let <= 'z') || (let >= 'B' && let <= 'Z')) {
                printf("hola");
            }
        }
    }
}

I have removed all the printing functions (And the others that you have put because I would not compile if I left them).

I hope it has helped you: D