I'm doing a script, and I've been stuck in one step.
My question is this:
Suppose that I have the variable prob = 0.8 , what I want is that prob is the variable that you choose between two objects. Example:
prob = 0.8
perro = "Soy un perro"
gato = "Soy un gato"
If prob is 0.8, it means that there is a 80% chance that the dog variable is chosen, and 20% that the cat is chosen.
Sorry if I did not include any example script, but I did not know how to ask it.
Regards, thanks.
On the Python base side, you have no way to set the probability of any of the random functions but nothing prevents you from using a way to simulate a specific probability, which is to work with a List that respects said distribution. In your example, it could be a list with 80 values "I am a dog" and 20 "I am a cat", then use random.choice() to get one or more values from that list. For example:
import random
perro = "Soy un perro"
gato = "Soy un gato"
prob = 0.8
cant = 100
lista = [perro]*int(prob*cant)+[gato]*int((1-prob)*cant)
resultados = {perro: 0, gato: 0}
for i in range(1000):
resultados[random.choice(lista)] +=1
prob_perro = (100*resultados[perro])/(resultados[gato] + resultados[perro])
print("Verificamos que probabilidad de {0} es de: {1}%".format(perro, prob_perro))
Doing this: cant = 100; lista = [perro]*int(prob*cant)+[gato]*int((1-prob)*cant) we generate a list with 100 values, 80 for "dog" and 20 for "cat", the number of cases will depend on the probabilities in this example of 80/20 with 100 values quickly we come to verify said probability empirically simulating up to 1000 cases of selection of a random element.
On the numpy side if you have a useful way to set the odds that is using numpy.random.choice() for example:
# Para generar 100 valores aleatorios con una probabilidad 80/20
print(numpy.random.choice([perro, gato], size = 100, p=[0.8,0.2]))
With size we indicate how many values we want to recover randomly and with p we indicate a probability list for each initial value.