Format specifiers in printf

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Format specifiers in printf

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#1 by (2 votes)

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Why this line exceeds 80 characters in width of a GNU / Linux or OSX console:

printf("%16s %16s %16s %16s %16s\n",
           "Artículo", "Cantidad", "Precio unitario", "Descuento", "Total");

Thanks in advance.

Best regards

c

asked by pelaitas 01.11.2017 в 18:31

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How can I make a sql that contains an array of objects and that those objects contain 2 column data? Access element, list list - Python

score 2 · Answer 1

The format specifier of the function

int printf ( const char * format, ... );

has the following scheme:

% [flags] [width] [. precision] [length] specifier

In the example you have the following:

printf("%16s %16s %16s %16s %16s\n",
           "Artículo", "Cantidad", "Precio unitario", "Descuento", "Total");

Note that the format specifier you use is % 16s . This will cause you to reserve 16 characters for each additional argument (...) . Then, considering that in the string you have as an argument:

"%16s %16s %16s %16s %16s\n"

5 additional arguments are expected, adding also 4 ( ' ' ) spaces that are specified in the string, this gives us the total of > 84 characters.