Delete repeated item entered by user

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Delete repeated item entered by user

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#1 by (2 votes)

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I'm recently watching C programming and we started with the fixes, there is an exercise where I have an N-size array with repeated numbers (entered by the user), what I'm asked to do is that the user enter a number and verify in the fix if it is found, in case it is so that it eliminates the position of the last repeated number (ex: 1 2 3 2 4>> 1 2 3 4), now if it only repeats once it eliminates directly. This last point I get, but when it comes to comparing if there are more repeated ends up doing anything, I send this to a new arrangement that is ours at the end. And well, that is a doubt / problem / situation, if someone were so kind to help me, I appreciate it. Greetings: D

[Edited]

int main(){
  int arr[n],nuevo[n],i,j,x,nro,cont,band=0;
  printf("Ingrese numeros, si son repetidos no importa\n");
  for(i=0;i<n;i++){
    printf("Ingrese el numero: ");
    scanf("%i",&arr[i]);
  }
  printf("Ingrese un numero a eliminar: ");
scanf("%i",&nro);
  for (i=0;i<n;i++) {
    cont=0;
    if(nro==arr[i]) cont++;
    if(cont==1){
      x=i;
      while(x<n){
        arr[x]=arr[x+1];
        x++;
      }
    }
  }
  for (i=0;i<n-1;i++)   printf ("%i ",arr[i]);

With this code what it does is eliminate the times that with the cont is 1, therefore it will always eliminate the same number to me, and what I want is that it is only the last position.

array c arreglos

asked by Edgardo_22 26.05.2017 в 21:32

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1 answer

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score 2 · Answer 1

The code has a few problems, but referring to the question: the problem is that when you delete a number and run the other elements, the counter goes to the next iteration and skips a number:

problem: 1 2 2 2 3

output: 1 2 2 3

when you check the second two, delete it and move the array, so it stays pointing to the next element, and when you give it to i ++ in the next iteration of the for you jump it

what you could do is [edited]

#include <stdio.h>

int main(){
  int arr[3], i, x, nro, cont;
  int n = 3;
  printf("Ingrese numeros, si son repetidos no importa\n");
  for(i=0;i<n;i++){
    printf("Ingrese el numero: ");
    scanf("%i",&arr[i]);
  }
  printf("Ingrese el numero para revisar: ");
  scanf("%i", &nro);
  cont = 0;
  for (i = 0; i < n; i++) {
    if (nro==arr[i]) {
      if (cont) {
        x = i;
        while(x<n){
          arr[x]=arr[x+1];
          x++;
        }
        i--;
        n--;
      }
      cont = 1;
    }
  }
  for (i = 0; i < n; i++) {
    printf("%i ", arr[i]);
  }
  printf("\n");
}