# what other functions can I add to this code of the Pythagorean theorem?

1

I need to know what else you can add about the Pythagorean theorem to the code I'm not very good about that and the Pythagorean theorem applies but I only did the basics of someone who tells me that another function I can add to it

Pd: tell me how good the code structure is Good and bad reviews are accepted.

``````#include <stdio.h>
#include <math.h>
#include <stdlib.h>

int main() {
int x,x1,x2;
float ca,ha,co,r,hp;
float rh,rh2;
float co1,ca1,rh1;
reinicio:

printf("por favor ingrese lo que dese hacer \n");
printf("(1) calcular tercer lado \n");
printf("(2) salir \n");
scanf("%i",&x);

if (x == 4){
exit(0);
}

printf("pero primero debe asignar el valor de las variables\n");
printf("utilice el siguiente el siguiente figura para guiarse\n");
printf("\n");
printf("                                                     \n");
printf("                             /|                      \n");
printf("                            / |                      \n");
printf("                           /  | c                    \n");
printf("                   a      /   | a                    \n");
printf("                  s      /    | t                    \n");
printf("                 u      /     | e                    \n");
printf("                n      /      | t                    \n");
printf("               e      /       | o    =(A)            \n");
printf("              t      /        |   a                  \n");
printf("             t      /         |   d                  \n");
printf("            o      /          |   y                  \n");
printf("           p  (c) /           |   a                  \n");
printf("          i  //  /            |   c                  \n");
printf("         h      /             |   e                  \n");
printf("               /              |   n                  \n");
printf("              /               |   t                  \n");
printf("             /                |   e                  \n");
printf("            /                 |                      \n");
printf("           /                  |                      \n");
printf("          /                   |                      \n");
printf("         /                    |                      \n");
printf("        /                     |                      \n");
printf("       /                      |                      \n");
printf("      /_______________________|                      \n");
printf("        cateto                                       \n");
printf("             opuesto    = (B)                        \n");

switch(x){
case 1:
printf("pro favor selecciones que lado desea calcular\n");
printf("(1)calcular hipotenusa\n");
printf("(3)calcular cateto opuesto\n");
scanf("%i",&x1);
if(x1 == 1){
printf("\n");
printf("ingrese el numero de cateto opuesto\n");
scanf("%f",&co);
printf("ingrese el numero de cateto adyacente\n");
scanf("%f",&ca);
printf("\n");

ca1 = pow(co,2);
co1 = pow(ca,2);
rh =  ca1 + co1;
rh1 = sqrt(rh);

printf("\n");
printf("el resultado es: %f\n",rh1);
printf("pero primero debe asignar el valor de las variables\n");
printf("utilice el siguiente el siguiente figura para guiarse\n");
printf("\n");
printf("                                                     \n");
printf("                             /|                      \n");
printf("                            / |                      \n");
printf("                           /  | c                    \n");
printf("                          /   | a                    \n");
printf("                         /    | t                    \n");
printf("            a           /     | e                    \n");
printf("           s           /      | t                    \n");
printf("          u           /       | o   = %f\n",ca);
printf("         e           /        |   a                  \n");
printf("        t           /         |   d                  \n");
printf("       o           /          |   y                  \n");
printf("      p  %f",rh1);printf(" /           |   a                  \n");
printf("     i  //       /            |   c                  \n");
printf("    h           /             |   e                  \n");
printf("               /              |   n                  \n");
printf("              /               |   t                  \n");
printf("             /                |   e                  \n");
printf("            /                 |                      \n");
printf("           /                  |                      \n");
printf("          /                   |                      \n");
printf("         /                    |                      \n");
printf("        /                     |                      \n");
printf("       /                      |                      \n");
printf("      /_______________________|                      \n");
printf("        cateto                                       \n");
printf("             opuesto  = %f\n",co);

printf("\n");
printf("Quiere volver a ejecutar el programa?\n ");
printf("(1)si\n");
printf("(2)no\n");
scanf("%i",&x);

if (x == 1){
system("cls");
goto reinicio;
}
if (x == 2){
exit(0);
}
}
if(x1 == 2){
printf("\n");
printf("ingrese el numero de cateto opuesto\n");
scanf("%f",&co);
printf("ingrese el numero de la hipotenusa\n");
scanf("%f",&hp);
printf("\n");

ca1 = pow(co,2);
co1 = pow(hp,2);
rh =  ca1 - co1;
rh1 = sqrt(rh);

printf("el resultado es: %f",rh1);
}
break;
}
}
``````

asked by Abdiel Josue Rodriguez 13.03.2017 в 02:57
source

1

I recommend you to explore what capabilities at the time of operating has the programming in C, obviously with the data you give and some more you could know the angle of the vertices, among others.

answered by 14.03.2017 в 01:02
1

You can add any function you find in a trigonometry book. Programming is a creative activity, use your imagination.

For example, in case 2 you can verify that the size of the leg is not bigger than the size of the hypotenuse.

``````if (cateto >= hipotenusa){
printf("ERROR: cateto >= hipotenusa\n");
}
``````

You can also invite the user to enter 3 numbers so that the code can verify if they form a rectangular triangle.

answered by 16.03.2017 в 20:26