How to read a txt file with an 8x11 matrix that has several char and put it in char [][] ?
The txt can have this form:
%,%,%,%,%,%,%,%,%,%,%
%,%,%,h,o,l,a,%,%,%,%
%,%,%,%,%,%,%,%,%,%,%
%,%,%,m,u,n,d,o,%,%,%
%,%,%,%,%,%,%,%,%,%,%
%,%,%,%,%,%,%,%,%,%,%
%,%,%,%,%,%,%,%,%,%,%
How do you read the previous txt from Java and put it as is with its rows and columns in char [][] ? Not in a vector [] , but in a matrix, respecting the rows and columns.
I would be using the BufferedReader class
Gets the instance to be able to read the file
public BufferedReader getBuffered(String link){
FileReader lector = null;
BufferedReader br = null;
try {
File Arch=new File(link);
if(!Arch.exists()){
System.out.println("No existe el archivo");
}else{
lector = new FileReader(link);
br = new BufferedReader(lector);
}
} catch (Exception e) {
e.printStackTrace();
}
return br;
}
We read the file line by line and save it in the character array
public void readTxt(){
try {
//ruta de tu archivo
String ruta = "archivo.txt"
BufferedReader br = getBuffered(ruta);
//leemos la primera linea
String linea = br.readLine();
//creamos la matriz vacia
char[][] = new char[8][11];
//contador
int contador = 0;
while(linea != null){
String[] values = linea.split(",");
//recorremos el arrar de string
for (int i = 0; i<values.length; i++) {
//se obtiene el primer caracter de el arreglo de strings
char[contador][i] = values[i].charAt(0);
}
contador++;
linea = br.readLine();
}
} catch (IOException | NumberFormatException e) {
e.printStackTrace();
}
}