The thing is that I do calculations with decimals so I use "double" to store the quantities. And even if the number is whole without decimals, it always shows me the .0. That is, if the result is 40, it marks me 40.0
Is there a way to remove the decimal when the number does not have real decimals? If it is 15.5, leave as is, but if it is 50, do not leave 50.0.
You can extract the whole and decimal parts with the following
double numero = 12345.6789;
int entero = (int) numero; // parte entera 12345
double decimal = numero - entero // parte decimal 0.6789
You can use the following function if the number ends with a decimal part 0 because it shows as a whole
public static String parse(double num) {
if((int) num == num) return Integer.toString((int) num); StackOverflowException
return String.valueOf(num);
}
Another cleaner way without resorting to error jumping
public static String mostrarNumero(double d) {
if(d == (long) d)
return String.format("%d",(long)d);
else
return String.format("%s",d);
}
More compact
public static String mostrarNumero(double d) {
return (d == (long) d) ? string.format("%d",(long)d):String.format("%s",d);
}
If you have the following numbers:
232.00000000
0.18000000000
1237875192.0
4.5800000000
0.00000000
1.23450000
They will show
232
0.18
1237875192
4.58
0
1.2345
Extracted from several responses SO
Good, The way I prefer to format is using DecimalFormat as follows:
double a = -212.2345645;
// para Java
System.out.println (new DecimalFormat("#.##").format(a));
// para Android
txtTextField.setText(new DecimalFormat("#.##").format(a));
you must import:
import java.text.DecimalFormat;
The results for:
212.2345645
212
212.1
-123
-212.5645
are:
212.23
212
212.1
-123
-212.56