Iterate an array of characters in c

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Iterate an array of characters in c

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#1 by (1 votes)

1

I want to print each element of the array but it generates a segmentation fault

This is the code:

#include <stdio.h>
int main(){
char arreglo[3]={'c','f','d'};
  char *puntero;
  puntero=arreglo;
  for(int i=0;i<3;i++){
      puntero+=i;
      printf("El valor de puntero es %s \n",*puntero);
}

}

If in printf instead of putting *puntero I only put puntero os so

printf("El valor de puntero es %s \n",puntero);

Print me like this:

cfd
fd 
d

I do not know what's wrong.

array c caracteres

asked by Karina 14.06.2018 в 23:11

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1 answer

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score 1 · Answer 1

To iterate an array of characters in c, you can do it by iterating the array and using %c to print characters in C.

int main() {
   char arreglo[3]={'c','f','d'};
  //char *puntero;
  //puntero=arreglo;
  for(int i=0;i<3;i++){
      //puntero+=i;
      printf("El valor del elemento: %d en el arreglo es: %c \n", i , arreglo[i]);
  }  
}

to have as output:

El valor del elemento: 0 en el arreglo es: c 
El valor del elemento: 1 en el arreglo es: f 
El valor del elemento: 2 en el arreglo es: d

For more information about how you specify the format to print, you can see this excellent response from @NaCl :

What is the use of the operator% in printf of variables in C language?