Create a new array based on another array, but without the repeated data

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Create a new array based on another array, but without the repeated data

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#1 by (1 votes)

1

As the title says, I am trying to create a second array based on an original array, but issuing the values that are repeated.

My problem is that the code does not work as I would expect, since whatever I do I can not generate the new array without repeating it successfully.

I thank you in advance.

Code:

String[] ape = new String[]{"Acevedo","Uribe","Osorio","Uribe","Acevedo","Correa","Milan"};
String[] nuevosApellidos= new String[ape.length];
    String temp="";
    int c=0;
    for(int k=0;k<e;k++){
        nuevosApellidos[c]= ape[k];
        temp= nuevosApellidos[c];
        List<String> iterador = Arrays.asList(nuevosApellidos);
        if(k>1){
            if(iterador.contains(temp)){
                System.out.println("El apellido "+temp+" ya estaba en el arreglo");
                if((k+1)<nuevosApellidos.length)nuevosApellidos[c]= ape[k+1];
                nuevosApellidos[c]="Vacío";
            }
        }
        c++;
    }

java array

asked by carlos puello 09.04.2018 в 04:11

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1 answer

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score 1 · Accepted Answer

Following the logic of your implementation, call a couple of things:

You always assign the value of a last name to the new arrangement, even though could be repeated: nuevosApellidos[c]= ape[k]
Just check if you have repeated for k > 1 so you could have k=0 and k=1 repeated.
It does not matter if the next if is fulfilled or not, you always overwrite it on the next line.
```
if((k+1)<nuevosApellidos.length)nuevosApellidos[c]= ape[k+1];
nuevosApellidos[c]="Vacío"
```

Instead:

You should only assign the new arrangement if it is not repeated

If repeated, you could assign "Vacío" or simply not increase the counter c

for (int k = 0; k < e; k++) {
    temp = ape[k];
    List<String> iterador = Arrays.asList(nuevosApellidos);
    if (iterador.contains(temp)) {
        System.out.println("El apellido " + temp + " ya estaba en el arreglo");
        nuevosApellidos[c] = "Vacío";
    } else {
        nuevosApellidos[c] = temp;
    }
    c++;
}