Problems with multiplication tables in PHP

Question

Problems with multiplication tables in PHP

Navigation

#1 by (1 votes)
#2 by (0 votes)

1

I'm doing some multiplication tables I've already done one with for worst I do with while and do while but I do not get the same result the for is this

<?php

for($t=8; $t<=10; $t++)
{

 echo "<h3> Tabla del $t </h3>";
 // generamos la tabla
 for($i=8; $i<=12; $i++)
 {
  echo "$t x $i = ".($t*$i) . "<br/>";
 }
}

?>

With while worse the same thing does not come out

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

<?php
$t=8;
$i=8;
while($t<=10){
    echo "<h3> Tabla del $t </h3>";
    $t++;
    while($i<=12){
        echo "$t x $i = ".($t*$i) . "<br/>";
        $i++;
    }
}

What can be my mistake?

php

asked by wdwd 03.10.2017 в 19:21

source

2 answers

1

You have a logic error when applying while .

For each round of the for , the first thing it does is initialize the counter variable and then start iterating ..

So internally, the for does something like this:

$i=8;

Your second while , does not. The first time i has the correct value, but then you never return to the source value, and there is the error.

You must move the instruction:

$i=8;

Before

while($i<=12){

and your problem will be resolved.

answered by 03.10.2017 в 19:31

what is the difference between a getElementsByTagNameNs () and a getElementsByTagName () SQL (ORACLE) How can I insert the current date into a table when inserting a record?

score 0 · Accepted Answer

Two point errors in your code

The increase of $t should be after the second while if it would not start from 9

The variable% co_of% after the second% co_of% remains at 13, then you should reset its value to% co_of% if you no longer enter the cycle of the second% co_of%

$t=8;
$i=8;
while($t<=10){
   echo "<h3> Tabla del $t </h3>";
   while($i<=12){
      echo "$t x $i = ".($t*$i) . "<br/>";
      $i++;
   }
 $i=8; //Reset variable
 $t++; //Incremento
}