I need to find files whose extension ends with a date format YYYYMMDD , in Linux I have the following command:
find . -regextype posix-extended -regex './.*.([0-9]{4})(0[1-9]|1[012])([12][0-9]|[0-9]|3[01]){2}'
But Solaris does not work, and tried in different ways but always ends in error.
You're very close, just a few tweaks in the regular expression are missing:
find . -regextype posix-extended -regex '.*\..*[0-9]{4}(0[1-9]|1[0-2])(0[1-9]|[12][0-9]|3[01])'
Description:
.*\..*[0-9]{4}(0[1-9]|1[0-2])(0[1-9]|[12][0-9]|3[01])
.* ::: any number of characters from the beginning \. ::: a literal point (it has to be escaped with the bar, otherwise it matches any character) .* ::: any number of characters from the point forward [0-9]{4} ::: 4 digits (year) (0[1-9]|1[0-2]) ::: a zero followed by 1 to 9, or a 1 followed by 0 to 2 (month) (0[1-9]|[12][0-9]|3[01]) ::: 0 followed by 1 to 9, or 1 or 2 followed by 0 to 9, or a 3 followed by a 0 or 1 (day)
Alternatively, you may not want to complicate yourself with so much validation, and just look for a file ending in 8 digits:
.*[0-9]{8}