different numbers java array

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different numbers java array

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#1 by (5 votes)
#2 by (2 votes)

3

The exercise consists of the following: given two arrays of 5 positions, we fill them with random numbers from 0 to 10 without repeating (until everything is correct) and then in a third array save the numbers from 1 to 10 have not been saved in any of the 2 arrays. Example: in array1 (1,2,3,4,5) array2 (1,4,2,3,8) in the third array (6,7,9, 10).

this is the code I've tried:

    int[] array1 = new int[5];
    int[] array2 = new int[array1.length];
    int numero = 0;
    for (int i = 0; i < array1.length; i++) {
        numero = rant.nextInt(10);
        if (repetidos(array1, numero) == false) {
            array1[i] = numero;
        }
    }
    for (int i = 0; i < array2.length; i++) {
        numero = rant.nextInt(10);
        if (repetidos(array2, numero) == false) {
            array2[i] = numero;
        }
    }
    System.out.println("array2");
    for (int i = 0; i < array2.length; i++) {
        System.out.print(array2[i]);
    }
    System.out.println("array1");
    for (int i = 0; i < array1.length; i++) {
        System.out.print(" " + array1[i]);
    }
    // guardar en un tercer array los numeros del 1 al 10 que no se hayan
    // guardado en ninguno de los 2 arrays
    int numero2 = 0;
    int numeroc = 10;// numero que se irá comparando a medida que vaya
                        // avanzando
    int posiciones = 0;
    for (int i = 0; i < array2.length; i++) {
        for (int j = 0; j < array1.length; j++) {
            if (array1[j] == numeroc || array2[i] == numeroc) {
                numeroc--;
            } else if (array1[j] != numeroc || array2[i] != numeroc) {
                posiciones++;
            }
        }
    }
    int[] array3 = new int[posiciones];// medida de el array definitivo

    for (int i = 0; i < array2.length; i++) {
        for (int j = 0; j < array1.length; j++) {
            for (int b = 0; b < array3.length; b++) {

                if (array1[j] == numeroc || array2[i] == numeroc) {
                    numeroc--;
                } else if (array1[j] != numeroc || array2[i] != numeroc) {
                    array3[b] = numeroc;
                }
            }
        }
    }
    System.out.println("array3");
    for (int i = 0; i < array3.length; i++) {
        System.out.print(array3[i]);
    }

}

public static boolean repetidos(int[] array, int numero) {

    boolean repetido = false;
    for (int i = 0; i < array.length; i++) {
        if (array[i] == numero) {
            repetido = true;

        }
    }
    return repetido;

and the output is as follows: array2 46810array1 9 3 1 0 2array3 10101010101010101010101010101010101010101010101010

What is the failure? What exactly have I failed? Is there any other way to do it?

java

asked by david sierra fernandez 17.05.2018 в 22:18

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2 answers

2

Your code has a problem.

The loop you use to fill array1 and array2 with random numbers has a failure because it leaves positions unfilled (to zero) when it is the case that a number is repeated. One solution is the following:

for (int i = 0; i < array1.length;) {
        numero = rant.nextInt(10);
        if (arrayContieneNumero(array1, numero) == false) {
            array1[i] = numero;
            i++;
        }
    }

You only have to increase the control variable when a number is not repeated . That's why I took it out.

On the other hand, the solution proposed by alanfcm seems right .

Greetings, David.

answered by 17.05.2018 в 23:13

Java doubt with equals () and with == SQL query by data type

score 5 · Accepted Answer

You can do it easier. You already have a function that tells you if an item is in an array, you just have to use it like this:

int b = 0;
for (int i = 0; i < 10; i++) {
  if(!repetidos(array1, i) && !repetidos(array2, i) {
     array3[b] = i;
     b++;
  }
}