Verify if there are whole numbers in a chain?

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Verify if there are whole numbers in a chain?

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#1 by (0 votes)

1

I have made this code:

 public static void main (String []args){
    Lexico lex = new Lexico();
    String cadena = JOptionPane.showInputDialog("Ingrese la cadena: ");
    System.out.println(lex.ingresarCadena(cadena));

 }   

    String[] Ecuacion1;
public  String ingresarCadena(String cadena)
    {
     String c ="";
     Ecuacion1 = cadena.split("(\+|\-|\*|\=|\%|\/)");
     for(int i = 0; i < Ecuacion1.length; i++)
    {
        System.out.print(Ecuacion1[i]);
    }
    return c;
 }

but I want to make a method that tells me if there are whole numbers in that vector.

java string array cadenas

asked by Chavarría Agudelo 24.10.2018 в 16:51

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1 answer

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score 0 · Accepted Answer

Your idea is correct, you can do it using a loop to check each character in the chain,

   private static boolean checkNumericValues(String cadena){        

      String[] caracteres =  cadena.split("");
      for(int i = 0; i < caracteres.length; i++)
        {
           try{             
                Integer.parseInt(caracteres[i]);             
                return true; //Existe al menos un caracter numerico.
           }catch (NumberFormatException e){ 
               System.out.println(" is not a valid integer number : " + e.getMessage()); 
           }                         
        }     

        return false; //No existen caracteres numericos

   }

but I think the best option would be using a REGEX to detect numerical values:

String regex = ".*\d+.*";

creates a method to verify if the string contains numeric values, if there is at least one numeric value the method will return true , otherwise false :

private static boolean checkNumericValues(String cadena){        

  String regex = ".*\d+.*"; 
  Pattern pattern = Pattern.compile(regex);      

  return  pattern.matcher(cadena).matches();

}