I want to include the space and only accept letters, numbers and accents and the special character > ñ . What I have done is the following:
if (primernombre.length() == 0 || a.matches(".*[^a-zñáéíóúA-ZÑÁÉÍÓÚ].*")) {
primernombre.setError("Ingrese un nombre valido. Solo letras.");
What I need is to include the space and the numbers.
For example: this is a text so far it does not accept it, and my regular expression accepts only thisis a text
Have you tried adding space in your set of characters?
Your expression would look something like this
a.matches("^[a-zñáéíóúüA-ZÑÁÉÍÓÚÜ0-9 ]$")
Edited
You can also try this expression:
^\w+( \w+)*$
This expression will allow a series of at least one word and the words will be divided by spaces.
^ Mark the beginning of the string
\w+ Indicates a series of at least one word of a character or number
( \w+)* indicates a group that repeats 0 or more times. In the group a space is expected followed by a series of at least one character or number.
$ indicates the end of the string
This can also be translated by the following expression:
^[a-zA-Z0-9ñáéíóúüÜÑÁÉÍÓÚ]+( [a-zA-Z0-9ñáéíóúüÜÑÁÉÍÓÚ]+)*$