How to capture the exception generated by a controller?

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How to capture the exception generated by a controller?

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#1 by (0 votes)

1

I have the following code that generates a report in PDF:

public void reporte(int ID)
{

            try{

            System.Data.DataSet ds = new System.Data.DataSet("Hoja_Salida");
            DataTable dtEmpresa = Empresa.Obtener(Convert.ToInt32(SessionManager.Item(SessionItems.fkEmpresa)));
            DataTable dtHojaSalida = DocumentoDetalle.ObtenerReporteHojaSalida(ID);



            dtEmpresa.TableName = "Encabezado";
            dtHojaSalida.TableName = "Detalle";

            ds.Tables.Add(dtEmpresa.Copy());
            ds.Tables.Add(dtHojaSalida.Copy());

            ds.Tables["Encabezado"].Columns.Remove("logo");
            ds.Tables["Encabezado"].Columns.Add("logo",Type.GetType("System.Byte[]"));



            Reportes.Reportepdf rp = new Reportes.Reportepdf();
            rp.SetDataSource(ds);

            BinaryReader stream = new BinaryReader(rp.ExportToStream(CrystalDecisions.Shared.ExportFormatType.PortableDocFormat));
            Response.ClearContent();
            Response.ClearHeaders();
            Response.ContentType = "application/pdf";
            Response.AddHeader("content-disposition", "attachment; filename=" + "Reporte.pdf");
            Response.AddHeader("content-length", stream.BaseStream.Length.ToString());
            Response.BinaryWrite(stream.ReadBytes(Convert.ToInt32(stream.BaseStream.Length)));
            Response.Flush();
            Response.Close();
            }

            catch(Exception ex)
            {
                 throw new Exception(ex.Message);
            }
}

and I execute it from the view in the following way:

 @{if(item.Folio != null){ <li><a href="@Url.Action("reporte", new { IDD= @item.ID})" class="fa fa-print">Hoja de salida sin costos</a></li> } else{}}

Someone can give me an idea of how to catch the exception and send it to view, to be able to send it to another controller through ajax.

c# ajax mvc

asked by mvega 27.01.2017 в 20:08

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1 answer

Read image in an ImagePanel Internet permission error

score 0 · Accepted Answer

One way to solve the problem you are presenting is to add the content of the exception to a session variable with Session["NombreDeLaVariableDeSesion"] :

public void reporte(int ID)
{
    try
    {
        //Código de tu reporte
    }
    catch(Exception ex)
    {
         HttpContext.Session["ExcepcionEnReporte"] = ex.Message;
    }
}

Then, in the view where the report was invoked, if an exception was generated we redirected to Controller :

@{
    if(item.Folio != null)
    { 
        <li><a href="@Url.Action("reporte", new { IDD= @item.ID})" class="fa fa-print">Hoja de salida sin costos</a></li>

        if(!string.IsNullOrEmpty(Session["ExcepcionEnReporte"].ToString())){
            RedirectToAction("ShowException", "Exception");
        }
    } 
    else { }
}

Now, in the ExceptionController , we read the session variable, we save it in the database and then we address it to the View to show the error message:

public class ExceptionController : Controller
{
    public string ExceptionMessage = string.empty;

    public ActionResult ShowException()
    {
        ExceptionMessage = HttpContext.Session["ExcepcionEnReporte"] != null ? HttpContext.Session["ExcepcionEnReporte"].ToString() : string.Empty;

        if(!string.IsNullOrEmpty(ExceptionMessage))
            //Guardado de la excepción en la base de datos

        //Guardamos el contenido de la excepción para luego mostrarla en la vista
        ViewBag.SpanExceptionMessage = ExceptionMessage;

        //Regresas un View para que se muestre el mensaje del error
        return View();
    }
}

Finally, we only show the message in the view using a <span> :

<span class="help-block">@ViewBag.SpanExceptionMessage</span>