The problem is that I pass a vector by reference and the terminal tells me it's wrong.
Here are the respective codes and errors:
ordenavector(&vector, cont);
test13.c: 21: 6: warning: passing argument 1 of 'ordenavector' from incompatible pointer type [enabled by default]
void ordenavector(int *vector[20], int numero);
test13.c: 2: 6: note: expected 'int **' but argument is of type 'int (*) [20]'
First of all it is not necessary to use a pointer to pass as a reference with a matrix, since the matrices and the pointers are compatible with each other with their castings ...
Example:
#include <stdio.h>
void SetMt(int* a, int b[])
{
a[0] = 2;
b[1] = 4;
}
int main()
{
// creamos una matriz:
int z[2]; // sz 2
SetMt(z, z);
printf("%d %d ", z[0], z[1]); // Salida: 24
}
I recommend that you read more about the pointers and matrices ...
2 topics:
Do not specify the size of the vector in the parameter, the definition of the function should be:
void ordenavector(int *vector, int numero);
By defining the vector as int unvector[20]; , the name itself is already a reference to its position in memory, so the call:
ordenavector(unvector,20);
is more than enough. It is equivalent to:
ordenavector(&unvector[0],20);
where you pass the memory position of the first vector object, which matches the address to which unvector refers.
Notice that the following is also correct:
ordenavector(&unvector[10],10);
but not:
ordenavector(&unvector.20);
since you are passing a pointer to an integers pointer.