Matrix length in Go

In Go, all the fixes that are created have a defined length and this is part of its type:

var array [10]uint8
var arrayOfArrays [7][3]uint8

In the first case, the variable array is an array of 10 elements of type uint8 and in the second the variable arrayOfArrays is an array of 7 elements where each element is an array of 3 elements of type uint8 That statement is equivalent to:

var arrayOfArrays [7]([3]uint8)

Now, Go has a built-in function called len() that returns an integer equivalent to the length of the object passed to it as a parameter, if the object is an array it returns the number of elements in that array. That means that:

len(array)

returns the number of array elements array (10). For arranging fixes arrayOfArrays (or the 'array', as you call it):

var filas = len(arrayOfArrays)

will return 7, because this variable is an array of 7 elements, where each element is also another arrangement, and

var columnas = len(arrayOfArrays[0])

will return 3, in this case the returned value is the number of elements of the first array that is itself an array element arraysOfArrays . If the objective is to know how many elements the arrangement of arrays has in total, the value is the multiplication of the variables rows and columns. Unlike other languages, in Go it is not possible to create an array of elements that are arrays of different sizes, so you can be sure that the number of elements [the length] of an array of arrays is the multiplication of the number of rows and columns.

var a [5][3]int; // declaration of the matrix

len(a); // size of the matrix columns

len(a[0]); // size of the rows of the matrix