I have a question, how can I compare between string and integer in Python? I want that if my data entered is a string, give me a message and if it is an int that my code continues.
Code that I tried:
n=raw_input("ingrese numero jugadores: ") if str==str(int):
print("escribe un numero, no una letra")
You can use the function raw_input , with it check if what you have entered is an integer and then continue with your idea.
while True:
n=raw_input("ingrese numero jugadores: ")
try:
n=int(n)
return n
except ValueError:
print "Escribe un numero, no una letra."
Another option is to directly check the type:
if type(n) !=int:
raise TypeError, "Escriba un numero"
Your question is a bit ambiguous, but I think what you are trying to do is to compare if a string is the representation of a whole number, if so, what can be done is this:
def is_int(s):
try:
return int(s)
except ValueError:
return False
if not is_int('hola'):
print('Es una cadena de caracteres no un entero')
if not is_int('14'):
print('Es una cadena de caracteres no un entero')
Based on what I understood your question, I have two interpretations
Assuming that the data entered is a string (from an input for example) ... and you want to check if they contain integers, you could do something like this:
entrada=input(">>")
if not entrada.isdigit():
print("Por favor usa solo números enteros")
else:
entero=int(entrada)
#Continuar la ejecución del código
In case you refer to a variable and want to check its type:
entrada="15" # un string
if type(entrada)==str:
print("no admito strings")
elif type(entrada)==int:
#operaciones con el entero
#Continuar con la ejecución del código
In the case of the latter, it will not accept data such as "15", but the first example would do so.
I hope I have helped.