Problem to open a default route with openFileDialog

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Problem to open a default route with openFileDialog

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#1 by (1 votes)

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Good morning. I'm trying to open a directory in a default route in the following way:

String directorio = Environment.CurrentDirectory + "\..\Pruebas";
 openFileDialog1.InitialDirectory = directorio;
 openFileDialog1.ShowDialog();

but it does not work for me, it sends me straight to the root of C. I appreciate your help in advance.

c#

asked by Arturo García Pérez 20.08.2018 в 19:08

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1 answer

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score 1 · Accepted Answer

Friend the solution I append my solution test if it works for you:

String directorio = System.IO.Path.GetFullPath(System.IO.Path.Combine(Environment.CurrentDirectory, @"..\..\..\Pruebas"));
openFileDialog1.InitialDirectory = directorio;
openFileDialog1.ShowDialog();