Error, I get an error that I do not understand, I'm starting

Navigation
0
  

Parse error: syntax error, unexpected '? > 'in C: \ xampp \ htdocs \ EPWeb \ Admin \ Presentation \ Aval.php on line 48

That error comes to me, I'm starting in php 

<section class="content">

    <div class="box">
        <div class="box-header with-border">
            <h3 class="box-title">Aval</h3>

            <button type="submit" class="btn btn-success btn-xs pull-right" value="Añadir" data-toggle="modal" data-target="#modal-default">
                <i class="fa fa-plus"></i> Añadir</button>

        </div>
        <!-- /.box-header -->
        <div class="box-body">
            <table class="table table-bordered">
                <tr>
                    <th style="width: 10px">#</th>
                    <th>Descripción</th>
                    <th>Acción</th>
                </tr>
                <?php

                $con = ConexionBD();
                $query= "SELECT * FROM aval";
                $ejecutar = mysqli_query($con,$query);

                where($mostrar == mysql_fetch_array($ejecutar)){ 


                ?>//esta es la linea 48




                <tr>
                    <td>
                        <?php echo $mostar['idaval'] ?> </td>
                    <td>
                        <?php echo $mostar['descripcionaval'] ?> </td>
                    <td></td>
                </tr>

                <?php
                    }
                  ?>
            </table>
        </div>

</section>
    
asked by Tevin Lectong 19.06.2018 в 18:42
source

1 answer

1
where($mostrar = mysqli_fetch_array($ejecutar)) {//este es tu error

while($mostrar = mysqli_fetch_array($ejecutar)) {//esta es la sintaxis
    
answered by 19.06.2018 в 19:02
PHP - Array does not take first value when selecting another line of text pick up link from which a file has been called .PHP