Here is my code php that what it does is show in JSON the information of the table.
if($_SERVER["REQUEST_METHOD"]=="POST"){
include('conexion.php');
$result = mysqli_query($con,"SELECT * FROM localidades").mysqli_error($con); //<<<<<<Aqui marca el fallo!
while ($row = $result->fetch_assoc()) {
$arr[] = $row;
}
$json = json_encode($arr);
echo $json;
}
ERROR
Object of class mysqli_result could not be converted to string
The error is quite clear, PHP uses the . point to concatenate two or more values, in its code it tries to concatenate a mysqli_result which is what returns mysqli_query , with a string that is what returns mysqli_error which is incorrect.
It should perhaps be just a if , to validate this
if ($result = mysqli_query($con, "SELECT * FROM localidades")) {
while ($row = mysqli_fetch_assoc($result)) {
$arr[] = $row;
}
$json = json_encode($arr);
echo $json;
}