Assign an intent to each item of a spinner

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Assign an intent to each item of a spinner

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#1 by (1 votes)

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Good, I have a spinner with the following values: Teacher and Student, my question is, how do I do it so that if the person chose Professor of the spinner direct him to a activity , but if you chose Student from spinner address another activity , so that my question is more understandable I leave my code

    Spinner tipuus;
    String[] tipos={"Elija una opción","Alumno","Profesor"};
    //---------------------------
    tipuus= (Spinner) findViewById(R.id.spntipusu);
    //---------------------------
    ArrayAdapter<String> listatipusu=new ArrayAdapter<String>(this,android.R.layout.simple_spinner_dropdown_item,tipos);
    tipuus.setAdapter(listatipusu);
    //---------------------------
    btnregistrar.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    if (tipuus.equals("Alumno")){
                         Toast.makeText(LoginActivity.this, "Usted a escogido alumno", Toast.LENGTH_SHORT).show();
                    }if (tipuus.equals("Profesor")){
                         Toast.makeText(LoginActivity.this, "Usted a escogido profesor", Toast.LENGTH_SHORT).show();
                    }else {
                        Toast.makeText(LoginActivity.this, "Usted no ha escogido un tipo de usuario", Toast.LENGTH_SHORT).show();
                    }
                }
            });

I know that the tipuus.equals("Alumno") part is wrong, I would like to know what the code would be like to do what I ask. Thanks

android-studio if spinner

asked by kevvelas 14.11.2017 в 06:04

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1 answer

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score 1 · Answer 1

To obtain the selected item within your spinner usas:

tipuus.getSelectedItem().toString().equals("alumno") // dentro del "" debe ir un String que exista en tu arreglo. es este caso alumno o profesor.

Then you must add an intent within a condition if :

Intent intent = new Intent(nombre_actividad_actual.this,nombre_actividad_destino.class);
                startActivity(intent);
                nombre_activdad_actual.this.finish();

It would stay like this:

 btnregistrar.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    if (tipuus.getSelectedItem().toString().equals("alumno"))){
                             Intent intent = new Intent(nombre_actividad_actual.this,alumno.class);
                startActivity(intent);
                nombre_activdad_actual.this.finish();

                    } else if (tipuus.getSelectedItem().toString().equals("profesor")){
Intent intent = new Intent(nombre_actividad_actual.this,´profesor.class);
                startActivity(intent);
                nombre_activdad_actual.this.finish();

                    }else {
                        Toast.makeText(LoginActivity.this, "Usted no ha escogido un tipo de usuario", Toast.LENGTH_SHORT).show();
                    }
                }
            });

As a note, you must differentiate the use of the if and the else if . the if evaluates all the conditions and the else if when finding one that is true stops and executes the action that is inside it. Help optimize your app.