My problem is that I capture 2 strings and then I want to save them in their arrangements
string nombre_buscado;
string apellido_buscado;
a
nombre[5][10]
apellido[5][10]
and I get the error in:
nombre[i]=nombre_buscado;
apellido[i]=apellido_buscado;
Thanks in advance.
What I see is that name [i] = searchname you need the location this would look like this: name [i] = searchname [i] and this goes inside a for so you can pass all the locations.
#include <string>
#include <iostream>
using namespace std;
int main()
{
string mensaje, otroMensaje[10];
int i;
mensaje = "Pedrito";
for(i=0;i<7; i++){
otroMensaje[i] = mensaje[i];
}
cout << endl;
for(i=0;i<7; i++){
cout << otroMensaje[i];
}
return 0;
}
You have to take into account that you are creating two-dimensional arrangements, so to store values in them, you have to indicate the positions where you will store them.
nombre[5][10]
nombre is a bi-dimensional array of 5 rows and 10 columns, if you want to store a value in that array you have to indicate the position of the row and the column where the value will be stored.
nombre[2][5] = nombre_buscado;
In this case, the value of the variable nombre_buscando will be stored in row 3 and column 4. In the arrangements the positions start counting from zero. If you have a 3-position arrangement, the positions will be: 0, 1 and 2.