Can you pass as parameters a function in another function in c ++?

  

Can you pass as parameters a function in another function in c ++?

You can.

Proposal.

Apparently the function you want to execute should be called cumplir_primera_condicion and get a matriz_juego (which looks like a two-dimensional array of something) and 7 additional parameters that appear to be numbers and return an integer.

C ++ is a strong typing language and static , this implies (among other things) that everything (including functions) has an underlying type, the types of C ++ functions follow the following format: retorno([parámetros...]) , so the type of your function could look like this:

int(char **, int, int, int, int, int, int, int)

To make it a function pointer you have to add the name after the return type:

int(*puntero_a_funcion)(char **, int, int, int, int, int, int, int)

And so it can be used:

int cumplir_primera_condicion(char **, int, int, int, int, int, int, int)
{
    // Hacer cosas
    return 0;
}

void funcion(bool(*puntero_a_funcion)(char **, int, int, int, int, int, int, int)) {
    if ((matriz_juego[i][j] == *casilla2 && matriz_juego[i][j-1] == *casilla2 &&  matriz_juego[i][j+1] == *casilla2)) {

        int d = puntero_a_funcion(matriz_juego,caracteres,puntaje, aleatorio.numero,aleatorio.numero2,aleatorio.numero3,i,j);
        if(j == 0){
            puntaje = d - 1;
        }
        if(j!= 0){
            puntaje = d;
        }
    }
}

// Llamar
funcion(cumplir_primera_condicion);

You can see that writing this is very cumbersome, so it is usually advised to use aliases of types:

int cumplir_primera_condicion(char **, int, int, int, int, int, int, int)
{
    // Hacer cosas
    return 0;
}

// Alias del tipo
using condicion_t = bool(char **, int, int, int, int, int, int, int)

// Llamada mas clara
void funcion(condicion_t *puntero_a_funcion) {
    ...
    ...
}

// Llamar
funcion(cumplir_primera_condicion);