I want to pass the results of the two queries in the same variable so that I can show it in a table, but I throw that error in the code, the code is as follows:
<?php
include("../BD-Config/config.php");
session_start();
// liste des événements
$json = array();
// requête qui récupère les événements
$requete = "SELECT * FROM evenement JOIN mis_contactos JOIN vehiculos
ON id_mec = id_meca AND id_usuario = id_user JOIN empresa WHERE evenement.id_user=1 AND empresa.id_meca=evenement.id_mec AND
evenement.id_vehiculo = vehiculos.id_vehiculo AND evenement.estado_cita>0 AND evenement.estado_cita<6 ORDER BY id DESC";
$querreque = "SELECT * FROM cita_autolavado JOIN vehiculos JOIN empresa WHERE id_user = 1 AND vehiculos.id_vehiculo = cita_autolavado.id_vehiculo AND id_meca = cita_autolavado.id_mec";
// connexion à la base de données
try {
$bdd = new PDO("mysql:host=".$servidor."; dbname=".$bd."; charset=utf8", $usuario, $pass);
} catch(Exception $e) {
exit('No se Pudo Conectar.');
}
// exécution de la requête
$resultat = $bdd->query($requete) or die(print_r($bdd->errorInfo()));
$risultato = $bdd->query($querreque) or die(print_r($bdd->errorInfo()));
$resulteichon = $risultato.$resultat;
//print_r($resultat->fetchAll(PDO::FETCH_ASSOC));
// envoi du résultat au success
echo json_encode($resulteichon->fetchAll(PDO::FETCH_ASSOC));
?>