Python: re.findall does not display digit strings correctly

0

My dear ones, I've been in this for awhile and I would like to know what I'm doing wrong.

I have this chain

  

/ file / items / show / 687 / file / items / show / 365 / file / items / show / 34 / file / items / show / 35 / file / items / show / 38 / file / items / show / 187 / file / items / show / 353 / file / items / show / 354 / file / items / show / 367 / file / items / show / 368 / file / items / show / 369 / file / items / show / 370 / file / items / show / 641 / file / items / show / 425 / file / items / show / 408 / file / items / show / 640 / file / items / show / 39 / file / items / show / 409 / file / items / show / 356 / file / items / show / 568 / file / items / show / 571 / file / items / show / 355 / file / items / show / 40 / file /...

And I wanted to find the digits using re.findall(r'\d+', cadena) . But the result is:

  

6,8,73,6,53,43,53,81,8,73,5,33,5,43,6,73,6,83,6,93,7,06,4,14 , 2,54,0,86,4,03,94,0,93,5,65,6,85,7,13,5,54,05,7,03,5,73,3,45,3 , 64.24,34,44,6,16,8,95,6,97,92,5,36,8,66,8,84,64,84,95,05,25,33,4,76 , 3.03,3,84,73,6,15,2,65,3,1

And of course, I want it to be 687,365,34,35...

Any suggestions?

    
asked by JairoM 04.10.2018 в 04:34
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0 answers