Arrangements of objects as compare [duplicate]

I would like to know how I can make my method print, print the object. and I run it in the bubble method, I also add my test code. Because what I print is

  

ordenamientos.Persona@15db9742 - ordenamientos.Persona@6d06d69c - ordenamientos.Persona@7852e922 - ordenamientos.Persona@4e25154f - ordenamientos.Persona@70dea4e -

public class Ordenamiento <E extends Comparable <E>> {
 private E elementos[];

public Ordenamiento(E [] arreglo){
    elementos =  arreglo;
}

public void imprimir() {
    for (int i = 0; i < elementos.length; i++) {
        System.out.print(elementos[i].getClass()+ " - ");
        if (i % 5 == 4) {
            System.out.println();
        }
    }
}

public void burbuja() {
    for (int i = 1; i < elementos.length; i++) {
        for (int j = 0; j < elementos.length - i; j++) {

            if ( (elementos[j].compareTo(elementos[j + 1])) < 0) {
                E aux = elementos[j];
                elementos[j] = elementos[j + 1];
                elementos[j + 1] = aux;

            }
            imprimir();
        }
    }
} 

TEST CLASS

public class TestOrdenamientoG {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
   Persona[] per = new Persona[5];

    Persona p0 = new Persona("Miguel");
    Persona p1 = new Persona("Vanessa");
    Persona p2 = new Persona("David");
    Persona p3 = new Persona("Jessica");
    Persona p4 = new Persona("Brenda");

    per[0] = p0;
    per[1] = p1;
    per[2] = p2;
    per[3] = p3;
    per[4] = p4;

    Ordenamiento or = new Ordenamiento(per);
    or.burbuja();

    System.out.println(per[0].getNombre());
    System.out.println(per[1].getNombre());
    System.out.println(per[2].getNombre());
    System.out.println(per[3].getNombre());
    System.out.println(per[4].getNombre());
}

}