I lose the reference in my Class with several constructors

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I lose the reference in my Class with several constructors

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#1 by (10 votes)
#2 by (0 votes)

2

I'm starting to do my tests in C# and I'm always running into the same problem.

When I create a class and I create several constructors, I always fail the constructor that does not contain parameters. Within the class, this constructor (the one that does not have parameters) constructs the object calling another constructor that if it receives parameters, the problem is that at a certain point the values of the parameters disappear. When I run the program in debug mode I see that the code works until it reaches a point the value of the variables are lost.

I put the code:

class Password
  {
    private int Longitud;
    private int Contraseña;

    public Password()
    {
        Password Password = new Password(8);
    }

    public Password(int Longitud)
    {
        this.Contraseña = Generar(Longitud);
    }

    private int Generar(int Longitud)
    {
        Random aleatorio = new Random();
        if (Longitud == 1)
        {
            return aleatorio.Next(0, 9);
        }
        else if (Longitud == 2)
        {
            return aleatorio.Next(0, 99);
        }
        else if (Longitud == 3)
        {
            return aleatorio.Next(0, 999);
        }
        else if (Longitud == 4)
        {
            return aleatorio.Next(0, 9999);
        }
        else if (Longitud == 5)
        {
            return aleatorio.Next(0, 99999);
        }
        else if (Longitud == 6)
        {
            return aleatorio.Next(0, 999999);
        }
        else if (Longitud == 7)
        {
            return aleatorio.Next(0, 9999999);
        }
        else if (Longitud == 8)
        {
            return aleatorio.Next(0, 99999999);
        }
        return -1;
    }

    public bool EsFuerte()
    {
        return Convert.ToString(Contraseña).Length > 5;
    }

    public void GenerarPassword(int Longitud)
    {
        this.Contraseña = Generar(Longitud);
    }

    public void MostrarPassword()
    {
        Console.WriteLine(Convert.ToString(Contraseña));
    }

    public int MostrarLongitud()
    {
        Longitud = Convert.ToString(Contraseña).Length;
        return Longitud;
    }

}
    // Este funciona OK
    Password pass1 = new Password(5);

    // Este me decuelve parametros vacios
    Password pass1 = new Password();

Example

If I build the object using the second constructor, the program works correctly for me and the value of the variables are the ones that have to be, whereas if I use the first one, the final result is not correct and the value of the variables is finished. losing for some reason (that will have its explanation but I do not know it).

It happens to me every time I create two constructors and one calls the other for abastecerse of parameters that the user ignores.

c#

asked by Edulon 25.07.2017 в 20:07

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2 answers

0

The correct way to call the second definition of the constructor

public Password() : this(8) {}

answered by 25.07.2017 в 21:16

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score 10 · Accepted Answer

public Password()
{
    Password Password = new Password(8);
}

This what it does is:

Enter the constructor without parameters to initialize the instance.

Create a new, different instance of Password by calling the constructor that accepts an integer.

Exit the constructor. The instance created with new Password(8) is no longer referenced, in due time the garbage collector will delete it.

If you want to delegate the initialization of the instance that you are initializing in another constructor, what is done is:

public Password() : this(8) {}