how to remove ALL the elements of a fix

0

In an arrangement I save the entire format of a table that I am placing in a PDF, I do it within a for .

At the next round he places the first and the second, when he only has to place the second because it is the second round.

How can I remove the contents of an ALL array so it cleans up?

for vuelta in range(mes,13):

    tabla_formateada = []
            vuelta=1
            for item in tabla_encabezado:
                tabla_formateada.append(Paragraph("<font size=%s><b>%s</b></font>" % (6, item),
                                                   rep.styles_reporte()['center']))
                vuelta=vuelta + 1
                if vuelta > 4:
                    tabla_formateada.append(Paragraph("<font size=%s><b>%s</b></font>" % (6, '%'),
                                                      rep.styles_reporte()['center']))
     tabla1 = [tabla_formateada]

     ano_inicio = int(ano_inicio) + 1

     '''se les da el tamaño a cada una de las columnas'''
      table = Table(tabla1, colWidths=tamano,
                      repeatRows=1)

      '''se le agrega el estilo ala tabla'''
      table.setStyle([('VALIGN', (0, 0), (-1, -1), 'TOP'),
                        ('BOX', (0, 0), (-1, -1), 0.30, colors.black),
                        ('BACKGROUND', (0, 0), (-1, 0), 
     colors.HexColor('#DFDFDF')),
                        ('INNERGRID', (0, 0), (-1, -1), 0.25, 
     colors.black)])
        story.append(table)
        story.append(Spacer(1, 10 * mm))

    doc.build(story)
    buff.close()

    buff = open(RECURSOS_DIR + '/pdf/vencimientos_tnr_mensual.pdf', 'rb')
    response.write(buff.read())
    
asked by Jonathan Garcia 13.08.2018 в 17:27
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0 answers