I would like to know what is the correct way to know when a file has information inside it.
Current code:
$myfile = fopen("app/vista/html5/encabezado/encabezado.html", "r") or die("Unable to open file!");
if ($myfile == false) {
echo "No tiene nada";
} else {
echo "Tiene algo";
}
fclose($myfile);
The only thing I'm looking for is to know if it has at least one character or line as content.
This can be achieved in the following way:
<?php
$archivo = "url o direccion del archivo";
if(filesize($archivo) > 0){
echo "El archivo tiene contenido";
} else {
echo "El archivo esta vacio";
}
?>
filesize returns the size of the file in bytes, or FALSE (and generates an error level E_WARNING) in case of an error.
If the file contains data, it must have a different size of 0 bytes, in the case of a plain text document.
You can use the filesize function. It determines the size of the file, without having to read it completely.
Here is a code using a ternary operator to determine if the file is empty or not.
Can be used in combination with file_exists to avoid a Warning in error_log, when the file does not exist:
EDIT: You have to deny the checks to make it work. I had escaped
$nombre_fichero = 'archivo.txt';
$vacio=(!file_exists($nombre_fichero) || !filesize($nombre_fichero)) ? FALSE : TRUE;
/*Prueba de la variable*/
var_dump($vacio);
When empty, the value of the variable will be:
bool(false)
And when you have data:
bool(true)
The advantage of this method is that it will also check whether the file exists or not. When it does not exist, the value will always be false .