I want to make a program where I ask the user names and he keeps them and orders them alphabetically.
This is what I have now:
names = input("What are the names? ")
print(names)
sorted_names = sorted(names)
print(sorted_names)
but when I run the program, this comes out
[' ', ' ', ' ', 'M', 'M', 'Z', 'a', 'a', 'c', 'c', 'i', 'l', 'o', 'o', 'p', 'r', 't', 't']
Sort each letter alphabetically.
How to make the names come out complete and ordered alphabetically?
The problem is that when you apply sorted to the string you convert the whole string into a list, that is, each character becomes an element of an ordered list.
You must create a list in which each name is an element and on it apply the ordering method. To do this, use the str.split method:
names = input("What are the names? ")
sorted_names = sorted(names.split())
print(sorted_names)
This is if you separate the names with spaces, otherwise pass to split the separator you want to use, for example to use a comma names.split(",") .
In case you want to order without having sensitivity to capitals (but without modifying the original string) you can use the key argument:
names = input("What are the names? ")
sorted_names = sorted(names.split(), key=lambda x: x.lower())
print(sorted_names)
If the user puts the names followed, separating by a comma, you can do so:
names = input("What are the names? ")
sorted_names = sorted(names.split(", "))
print(sorted_names)
If so, you can solve it that way, but rethink the question.
Greetings
You can opt for a while loop that adds names to a list infinitely until you type a "keyword" in this case "Print".
When you enter "Print" the list is sorted by the .sort () command and printed.
nombre = input("Ingrese un nombre: ")
Lista = []
while nombre != "Imprimir":
Lista.append(nombre)
nombre = input("Ingrese otro nombre: ")
Lista.sort()
print(Lista)