I have the following array of characters:
char caracteres[10] = {'1', '2'};
And the next uint8_t (its size is 1 byte):
uint8_t resolucion;
What I want is to store the 12 (as a number) within the variable resolucion . I have tried some things but they have not worked for me. Any suggestions?
Assuming you have this:
char caracteres[10] = {'1', '2'};
If you have not already done so, you should end the string with ' : '0''
char caracteres[10] = {'1', '2', 'char caracteres[10] = "12";
' };
With what would be equivalent to this:
uint8_t resolucion = 0;
for( char* ptr = caracteres; *ptr; ++ptr )
{
resolucion *= 10;
resolucion += *ptr - '0';
}
The whole step is as simple as using a loop:
'9' - '0' = 9
'5' - '0' = 5
'1' - '0' = 1
'0' - '0' = 0
That is, it is iterated by the sequence of characters and each one is subtracted the digit %code% (do not forget that the character is the representation of a number). Reviewing an ASCII table is easy to see that:
char caracteres[10] = {'1', '2'};
You can convert a character string to a number with the std::stoi ( s ) utility % tring to i nteger) present in the header <string> :
char caracteres[10] = {'1', '2'};
uint8_t resolucion = std::stoi(caracteres);
Keep in mind that std::stoi returns int no uint8_t , so there could be data narrowing, but if your resolución will always fit in 8bits it should not be a problem.
Also keep in mind that passing% co_of% non-transformable values to number can throw an exception std::stoi .