I am making a regular expression to find all the words in a sentence. I have the following:
import re
emoji_pattern = re.compile('[A-Za-z]+')
print(emoji_pattern.search("jajaja que haces?"))
But when I run it, it gives me
<_sre.SRE_Match object; span=(0, 6), match='jajaja'>
that just says the word jajaja .
She is the only one who finds, but nevertheless she should give all the words.
A simple option is to use re.findall () , such as described @ TheSupermax03 .
A more efficient option is to use re.finditer () , which generates a iterator, especially if it is a long text.
import re
regex = r"[A-Za-z]+"
texto = "jajaja que haces?"
for match in re.finditer(regex, texto):
print( match.group(0) )
jajaja
que
haces
In addition, re.finditer () allows you to obtain the text captured by each group, in each coincidence.
* and works well with empty matches, where findall skips 1 character.
What happens is that search returns the first match you find according to the regular expression you used, so in your case it returned jajaja . If you want to find all the occurrences you can use findall. Your code with findall would be as follows
import re
emoji_pattern = re.compile('[A-Za-z]+')
print(emoji_pattern.findall('jajaja que haces?'))
The output is as follows:
['jajaja', 'que', 'haces']
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