I have this code to get the availability of any URL, but when using in_array () , whenever I compare it gives me a result of FALSE. I would like to know what I am doing wrong or is in terms of the type of variable treatment.
$headers = get_headers('http://www.example.com/');
//print_r(sscanf( $headers[0], 'HTTP/%*d.%*d %d'));
$accept = array( 200, 301, 302 );
if(in_array($headers[0], $accept)){
echo "Disponible";
} else {
echo "No disponible";
}
According to the Manual, the get_headers information comes as follows:
Array
(
[0] => HTTP/1.1 200 OK
[1] => Date: Sat, 29 May 2004 12:28:13 GMT
[2] => Server: Apache/1.3.27 (Unix) (Red-Hat/Linux)
[3] => Last-Modified: Wed, 08 Jan 2003 23:11:55 GMT
[4] => ETag: "3f80f-1b6-3e1cb03b"
[5] => Accept-Ranges: bytes
[6] => Content-Length: 438
[7] => Connection: close
[8] => Content-Type: text/html
)
As you can see, the status code comes with other data: HTTP/1.1 200 OK for code 200 .
Therefore, your code will never work.
This can be resolved in several ways.
The simplest would be using cURL .
Something like this:
$url="http://www.example.com";
$handle = curl_init($url);
curl_setopt($handle, CURLOPT_RETURNTRANSFER, TRUE);
$response = curl_exec($handle);
$responseCode = curl_getinfo($handle, CURLINFO_HTTP_CODE);
$accept = array( 200, 301, 302 );
if(in_array($responseCode, $accept)){
echo "Disponible";
} else {
echo "No disponible";
}
curl_close($handle);
If it were the url of the script itself, you can get the response code with the use of http_response_code() .
Another option would be to extract the code using regular expressions. But we should see if the answers are all standard.
And another option would be to do a partial search of the values of your array in the key [0] of the header. In other words, look for values such as HTTP/1.1 200 OK * that contain the value 200 or 301 or 302 .