Problem with .htaccess

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Problem with .htaccess

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#1 by (0 votes)

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The problem is this:

I want to generate a url of the type link

I have put the following in the htacces:

RewriteEngine On
RewriteCond %{HTTP_HOST} ^(.*\.)*midominio.com$ [NC]
RewriteCond %{SERVER_PORT} !^443$
RewriteRule ^(.*)$ https://www.midominio.com/$1 [R]
RewriteRule ^(\w+)/?$ post.php?id=$1 [L,R]

and in the php file that makes the call I have put the following:

$url_dinamica = "post/".$url_que_genero_dinamicamente;

As it is now, it makes me perfectly call the post.php file, commenting that this is a unique file in which I change the values by variables that I take from the DB.

The problem is that it currently shows me the URL in this way:

link

and what I want is the following:

link

that is, I want you to remove the post.

The generated file does not exist, it is generated dynamically by the post.php file, changing the content of the variables it collects from the database.

.htaccess

asked by Alfonso 18.05.2018 в 21:28

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1 answer

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score 0 · Answer 1

Try this:

if the filename of what I'm asking is not a file (example: /post.php)
if the filename of what I'm asking is not a folder (example / css)
then take everything that comes as filename and pass it to post.php as id

RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^(.+)$ post.php?id=$1 [L]

and you generate the url like this:

$url_dinamica = "/".$url_que_genero_dinamicamente;

If you give a blank screen there may be redirects due to other rules in the .htaccess or silently fail the post.php , in that case you have to go testing taking rules of .htaccess , pulling var_dump / print_r , etc ... to see where the error is.

A complete redirecting example for "pretty urls", simulating a DB in an array:

index.php

<?php require_once('falsaDB.php'); ?>
<html>
<head>
  <title>Post Example Index</title>
</head>
<body>
  <ul>
    <?php foreach ($tablaPOSTS as $key => $value) : ?>
      <li><a href="./<?php echo $value['slug'];?>" ><?php echo $key.". ".$value['titulo'];?></a></li>
    <?php endforeach; ?>
  </ul>
</body>

falsaDB.php

<?php
$tablaPOSTS = array(
  array('ID'=>0, 'titulo'=>'Un enlace bonito', 'texto'=>'El texto de un enlace bonito'),
  array('ID'=>1, 'titulo'=>'Un post cualquiera', 'texto'=>'El texto de un post cualquiera'),
  array('ID'=>3, 'titulo'=>'Otra prueba de re escritura', 'texto'=>'El texto de otra prueba de re rescritura'),
);

// genero los slugs a partir del título, 
// esto debería hacerse al insertar el registro
foreach($tablaPOSTS as $key=>$post):
  $tablaPOSTS[$key]['slug'] = strToLower(str_replace(' ', '-', $post['titulo']));
endforeach;

// Simulo un select post from tabla where slug=$slug
function findPOSTbySlug($slug, $tabla){
  $key = array_search($slug, array_column($tabla, 'slug'));
  return ($key)?$tabla[$key]:"'$slug' NO ENCONTRADO";
}
?>

post.php

<?php require_once('falsaDB.php'); ?>
<html>
<head>
  <title>Post Example</title>
</head>
<body>
  <?php
      $elSlug = $_REQUEST['id'];
      $resultado = findPOSTbySlug($elSlug, $tablaPOSTS);
      if (is_array($resultado)) :
  ?>
  <h1><?php echo $resultado['titulo'];?></h1>
  <p><?php echo $resultado['texto'];?></p>
  <?php else : ?>
  <p><?php echo $resultado;?></p>
  <?php endif; ?>
  <pre>
    <?php print_r($resultado); ?>
  </pre>
</body>
</html>

.htaccess

RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^(.+)$ post.php?id=$1 [L]

I changed the matching pattern to pass the "filename" to post.php as id
In case you want to pass additional parameters for example /otra-prueba-de-re-escritura?pagina=2 the pagina=2 you get it from $_SERVER["REQUEST_URI"] which would be the original url untransformed.
if it is shared hosting or there are several virtualhost you may have to add RewriteBase / just before the first RewriteCond , sometimes it also has a rule with [R] just before or one level higher.