Yes. with diff ()

The diff () function has the following syntax

 diff(F)
 diff(F,var) 
 diff(F,n) 
 diff(F,var,n)
 diff(F,var1,...,varN)

To achieve what you propose:

Derived from a function of a variable:

syms x
f(x) = sin(x^2);
df = diff(f,x)

df(x) =
2*x*cos(x^2)

Derive functions of several variables

finds the first derivative of the expression

syms x t
diff(sin(x*t^2))

ans =
t^2*cos(t^2*x)

Since the variable to derive diff is not specified, it uses the default variable defined by symvar for that expression the variable is x:

symvar(sin(x*t^2),1)

ans =
x

Now to find the derivative of the expression with respect to the variable t:

diff(sin(x*t^2),t)

ans =
2*t*x*cos(t^2*x)

With information translated from diff () in MathWorks