PHP array problem, echo shows me array

Question

PHP array problem, echo shows me array

Navigation

#1 by (0 votes)
#2 by (0 votes)

0

 while (true) {
     $t= "SELECT MAX(id) AS id FROM accidente";

        $query2=mysqli_query($db,$t);
        while($acd[]=mysqli_fetch_array($query2))

$last= current($last_id);
$acd_1=current($acd);
 $ls=(( $last !== false) ? $last : ", &nbsp;");
 $acd2=(( $acd_1 !== false) ? $acd_1 : ", &nbsp;");
                $valores3='("'.$ls.'","'.$acd2.'"),';
                $valoresQ3= substr($valores3, 0, -1);


            $acd_impl="INSERT INTO implicado_acd (id_acd, id_implicado) VALUES $valoresQ3";
            $sqlRess1=$db->query($acd_impl) or mysql_error();

    $last = next($last_id);
    $acd_1= next($acd);
    if($last === false) break;
                        echo "...".$acd;

php mysqli

asked by Carlos Alberto Soler Velasquez 16.06.2017 в 04:04

source

2 answers

Problem with exporting the data to an excel, I do not save the data in the excel it leaves blank Generate PDF from stream

score 0 · Answer 1

0

Change the:

echo "..." . $acd;

For a

print_r($acd);

Since your problem is that you are trying to do an echo of an array.

answered by 16.06.2017 в 09:09

score 0 · Answer 2

How well does NetVicious comment with:

Print_r: Print human-readable information about a variable
Var_dump: Shows information about a variable
```
print_r($array);    var_dump($array);
```

Both internal php functions will help you display the contents of the array on one line.