Error "Operand of * must be a pointer" when creating pointer with malloc and using it in a FOR

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#1 by (3 votes)

2

I'm trying an example of the book "Understanding and using Pointers" that has this code:

int main()
{
    char *pc = (char*)malloc(6);

    for (int i = 0; i < 5; i++)
    {
        *pc[i] = 0;
    }

    return 0;
}

In theory, it should work, but I get the error:

Operand of * must be a pointer.

Can you tell me what's wrong? I am using Visual Studio 2015 Community.

c

asked by Sergio Calderon 13.10.2016 в 17:48

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1 answer

Navigating a JSON Better performance in consultation with BD Oracle

score 3 · Accepted Answer

3

The error is that to refer to the pc variable inside the loop, you no longer have to use the pointer symbol.

pc[i] = 0;

That way you initialize the memory.

If you want to copy the character 0, add single quotes:

pc[i] = '0';

answered by 13.10.2016 / 18:05

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