Why could I initialize a string with a direct initialization but not with a reference?

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Why could I initialize a string with a direct initialization but not with a reference?

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#1 by (0 votes)

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Because I can initialize a string with a direct initialization

string tentative("TENTATIVE");
string motAffiche = tentative;

but not with a reference

string tentative("TENTATIVE");
string motAffiche = tentative;

Indeed, gedit tells me that

error: conversion from 'std :: __ cxx11 :: string * {aka std :: __ cxx11 :: basic_string *} 'to non-scalar type 'Std :: __ cxx11 :: string {aka std :: __ cxx11 :: basic_string}' requested

Is it as if motAffiche and tentative have the same object, no?

c++

asked by ThePassenger 14.03.2017 в 02:21

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1 answer

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score 0 · Answer 1

I guess in your original code you really mean this

int main(int argc, char *argv[])
{
    string tentative("TENTATIVE");
    string motAffiche = &tentative;

    return 0;
}

It actually returns an error because you are trying to assign the address of the string object called tentative to a variable of type string which is incompatible since the variable motAffiche should be a pointer to string.

I suppose that in your question you refer to the c ++ references and not to simple pointers, so one way to achieve what you want would be like this.

int main(int argc, char *argv[])
{
    string tentative("TENTATIVE");
    string& motAffiche = tentative;

    cout<<tentative<<endl;
    cout<<motAffiche<<endl;

    cout<<&motAffiche<<endl;
    cout<<&tentative<<endl;



    return 0;
}

In the example the last two "cout" print the memory addresses of the objects which should be the same since in the second variable we are referring to the first one.