display html files from a directory in a php

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display html files from a directory in a php

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#1 by (3 votes)
#2 by (0 votes)

2

I have a directory with html files that are articles (no header or footer, I want to show all those html files in a php called articles.php with a link to access them (the article.php file has a header and footer by require ()

Finally, what I want is to show the article as articulo.php? articulpo.html but with the header and footer of the article php file

html php

asked by Marlon Camacho Polo 14.07.2016 в 17:53

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2 answers

State File Accountant AngularJs create a drop-down sidebar menu

score 3 · Answer 1

For this question, I'm going to imagine that your website has a structure like this (it's probably a bit different, adapting the code should to your structure should be simple):

/
├ index.php
├ articulo.php
├ encabezado.php
├ pie.php
└ articulos/
     ├ articulo1.html
     ├ articulo2.html
     ├ articulo3.html
     ├ ...

In your file articulo.php is where you have the header and foot with a require() , then what you should do is the following:

Pass the article that you want included in the header

Read in% co_of% what article

Add the article's html using $_GET or require() (as you're already doing for the header and footer)

Whereas the article would be passed in the header as follows: include() , then this would be done as follows in articulo.php?articulo=articulo1 ,:

<?php

    // incluimos la cabecera
    require("cabecera.php");

    // si se ha pasado el articulo y existe su fichero html
    $articulo = filter_input(INPUT_GET, "articulo"); 
    if (isset($_GET["articulo"]) && file_exists("articulos/$articulo.html")) {
        // se incluye en la página
        require("./articulos/$articulo.html");
    } else {
        // si no se ha pasado id del artículo o no existe, se muestra un error
        echo "Artículo no especificado o no existente.";
    }

    // incluimos el pie
    require("pie.php");

score 0 · Answer 2

$extension = ".html";



$directorio = '/tmp';
$dir = opendir($directorio);

while ($archivo = readdir($dir)){
 if (!is_dir($archivo)){//Validamos q no se abra otra carpeta
    if(strpos($archivo, $extension)){
      ///SE ENCONTRO ARCHIVO HTML
    }
 }
}