$formacademica = new Formacademica;
$userCorreo = Auth::user()->email;
$userCorreo = Auth::user()->email; /*Aqui solo capturo el usuario que ha iniciado sesión*/
$aspirantes[] = DB::table('aspirantes')->where('correo_asp',$userCorreo)->first();
/*en esta parte lo que hago es poner una condición con where, donde comparo el campo
correo_asp con la variable $userCorreo, para obtener los datos que tiene ese correo. Y es donde tengo el error*/
Dear, this type of PHP error indicates that you are using a variable with a scalar value ( string , float or integer ) as an array. When you try to do this, PHP sends a warning, this you can check with the function is_scalar of PHP that lets you know if a variable is scalar.
According to the code you offer, I think that when you use $aspirantes[] is when you throw this exception, you must first check that this variable is initialized as a array or verify that it was not previously created as a scalar variable.
Try it this way:
$userCorreo = Auth::user()->email;
$userCorreo = Auth::user()->email;
$aspirantes = DB::table('aspirantes')->where('correo_asp',$userCorreo)->get();
in the view you go through it like this:
@foreach($aspirantes as $asp)
{{$asp->correo_asp}}
@endforeach
Why the brackets?
It should just be like this
$aspirantes = DB::table('aspirantes')->where('correo_asp',$userCorreo)->first();
The query you are doing only returns an object, not an array, it is not necessary to use a foreach
Now in the view you should place something like the following
<div class="col-md-3">
<div class="form-group row">
<div class="col-sm-12">
@if($aspirantes)
{{ $aspirantes->id_asp }}
@endif
</div>
</div>
</div>
I think they answered the same thing in another question you did.