Get file in relative path of runnable jar

Question

Get file in relative path of runnable jar

Navigation

#1 by (2 votes)

2

I have been trying for hours to read a file that is in the same directory as the executable JAR:

My code is:

Object obj = parser.parse(new FileReader("configuracion.json"));

But I already tried with

"./ configuracion.json"

". \\ configuracion.json"

I tried putting it in a "resources" folder in the root of the project and doing the ...getResource("configuracion.json").getPath() but it also did not work when exporting, only during the debug in Eclipse.

When I run it in Eclipse (the configuration.json is in the root of the project) it works, but when I export it to a Runnable JAR it throws FileNotFoundException .

If someone could give a hand I would appreciate it very much.

java

asked by Genarito 04.01.2018 в 18:07

source

1 answer

how to go back to a specific line of the code? Correctly display characters encoded in style \ xe9 [duplicated]

score 2 · Accepted Answer

To avoid this type of situation, I have a function that searches the directory and checks if the path to return is correct. Edited taking into account the comments

 /**
 * Obtenemos la ruta hasta el fichero , habitualmente situado junto al
 * archivo JAR. En caso contrario, estariamos ejecutando desde un IDE y
 * buscaremos el archivo junto al pom.xml y las carpetas target y src.
 *
 * @param filename nombre fle fichero(con extension) a abrir
 * @return Ruta completa hasta el fichero
 * @throws URISyntaxException
 * @throws IOException
 */
public static String getRutaRecurso(String filename) throws URISyntaxException, IOException {
    final ProtectionDomain domain;
    final CodeSource source;
    final URL url;
    final URI uri;
    String DirectoryPath;
    String separador_directorios=System.getProperty("file.separator");
    String JarURL;
    File auxiliar;
    domain = Fichero.class.getProtectionDomain();
    source = domain.getCodeSource();
    url = source.getLocation();
    uri = url.toURI();
    JarURL = uri.getPath();
    auxiliar = new File(JarURL);
    //Si es un directorio es que estamos ejecutando desde el IDE. En este caso
    // habrá que buscar el fichero en la carperta  abuela(junto a las carpetas "src" y "target·
    if (auxiliar.isDirectory()) {
        auxiliar = new File(auxiliar.getParentFile().getParentFile().getPath());
        DirectoryPath = auxiliar.getCanonicalPath() + separador_directorios;
    } else {
        JarURL=auxiliar.getCanonicalPath();
        DirectoryPath = JarURL.substring(0, JarURL.lastIndexOf(separador_directorios) + 1);

    }

    System.out.println(DirectoryPath + filename);
    return DirectoryPath + filename;
}

In your specific code, it would be adding this in the following way and having the file next to the jar

Object obj = parser.parse(new FileReader(getRutaRecurso("configuracion.json")));

Take a look to see if it works for you