Well, let's start.

What I would do would be to make a string with the number and a space, and then print the string

```
numero=int(input("numero n: "))
numcol=0
while numcol<numero:
fila=numcol+1
cont=0
m=""
while(cont<fila):
m=m+str(numcol+1)+" " # si no necesitas el espacio, seria m=m+str(numcol+1)
cont+=1
print m
numcol=numcol+1
```

Basically, row would keep the number that goes in each row, for example, if it is row 1, then save the 1, and so on.
With cont, what I do is repeat that number the same number of times that number dictates, if row is equal to 1, then, m will be equal to "1", if row is equal to 2, m will be equal to "2" 2 "and then, with the print m, I'm showing the rows below the other one, if you enter n = 5 in this way:

```
1
2 2
3 3 3
4 4 4 4
5 5 5 5 5
```

See that I did not put, numcol less than or equal to number, but less strict, since if equal, would repeat n + 1 times and the last row of the previous example would be `"6 6 6 6 6 6 "`

Greetings and I hope you serve!