I am making a query in SQLServer where I require the record of days worked of x number of employees.
On the days when they are at Rest, they can work obtaining the additional day.
The query I have generates the following
id cliente puesto empleado anno mes dia turno
1 ACME PUERTA CORRECAMINOS 2016 6 1 001
1 ACME PUERTA CORRECAMINOS 2016 6 2 DESCANSO
1 ACME BODEGA CORRECAMINOS 2016 6 3 001
1 ACME BODEGA CORRECAMINOS 2016 6 4 001
1 ACME PUERTA CORRECAMINOS 2016 6 5 001
1 ACME BODEGA CORRECAMINOS 2016 6 6 001
1 ACME BODEGA CORRECAMINOS 2016 6 7 001
1 ACME PUERTA CORRECAMINOS 2016 6 8 001
1 ACME BODEGA CORRECAMINOS 2016 6 9 DESCANSO
2 ACME BODEGA CORRECAMINOS 2016 6 9 001 EXTRA
1 ACME BODEGA CORRECAMINOS 2016 6 10 001
1 ACME BODEGA CORRECAMINOS 2016 6 11 001
1 ACME BODEGA CORRECAMINOS 2016 6 12 001
1 ACME BODEGA CORRECAMINOS 2016 6 13 001
1 ACME BODEGA CORRECAMINOS 2016 6 14 001
1 ACME BODEGA CORRECAMINOS 2016 6 15 DESCANSO
On the 9th he was resting but he worked the day as an extra shift, what I need is that I do not get duplicated on day 9 but show only the record with the extra shift.
My query is something like this:
select id_registro, cliente, puesto, empleado,
DATEPART(YEAR,fecha) anno, DATEPART(MONTH,fecha) mes,
DATEPART(DAY,fecha) dia, turno
from programacion
where DATEPART(YEAR,fecha)=2016 and DATEPART(MONTH,fecha)=6
The result I need would be:
id cliente puesto empleado anno mes dia turno
1 ACME PUERTA CORRECAMINOS 2016 6 1 001
1 ACME PUERTA CORRECAMINOS 2016 6 2 DESCANSO
1 ACME BODEGA CORRECAMINOS 2016 6 3 001
1 ACME BODEGA CORRECAMINOS 2016 6 4 001
1 ACME PUERTA CORRECAMINOS 2016 6 5 001
1 ACME BODEGA CORRECAMINOS 2016 6 6 001
1 ACME BODEGA CORRECAMINOS 2016 6 7 001
1 ACME PUERTA CORRECAMINOS 2016 6 8 001
2 ACME BODEGA CORRECAMINOS 2016 6 9 001 EXTRA
1 ACME BODEGA CORRECAMINOS 2016 6 10 001
1 ACME BODEGA CORRECAMINOS 2016 6 11 001
1 ACME BODEGA CORRECAMINOS 2016 6 12 001
1 ACME BODEGA CORRECAMINOS 2016 6 13 001
1 ACME BODEGA CORRECAMINOS 2016 6 14 001
1 ACME BODEGA CORRECAMINOS 2016 6 15 DESCANSO
I tried MAX (id) but it does not work.