For example with this pseudocode
function suma(a,b)
{
return a+b
}
function callfun(namefunction,arg1,arg2)
{
namefunction(arg1,arg2)
}
I also need to know how to make a console and from the console I write this to call the sum function
callfun(suma,3,3)
Short answer: No but Yes.
Long answer:
What you propose is typical of interpreted languages, which can Locate functions by name at runtime.
C is compiled , and it does not allow factory to do what you indicate. However, an approximation is possible, but with function pointers
void function1( int a ) {
...
}
void call( void ( *f )( int ), int v ) {
*f( v );
}
void ( *ptr )( int ) = function1;
call( ptr, 10 );
To select one of several functions, you can use a structure and an arrangement:
struct ident {
char *name;
void ( *ptr )( void );
};
struct ident functions[];
And you go through the arrangement looking for the indicated name.
And, if you want more flexibility, you use functions with variable arguments:
#include <stdarg.h>
void funct( const char *fmt, ... ) {
va_list ap;
va_start( ap, fmt );
...
va_end( ap );
}
and declare the pointer as
void ( *pointer )( const char *, ... );
I think that with the above and you can go pulling some code to show us ...
Functions are always called at runtime, that's when the program opens.
For the sum is easy, instead of function , it should be float , and the parameters a and b should be float too, since it is a sum of real numbers.
float suma(float a,float b)
{
return a+b;
}
The callfun function, as it does not have the return statement, returns a void , but the parameters, we do not know what type they are, so I name them, Tipo_1_1 , Tipo_1_2 , Tipo_1_3 , Tipo_2 and Tipo_3 , but it could be any type of data, void , int , char .
void callfun(Tipo_1_1 (*namefunction)(Tipo_1_2,Tipo_1_3),Tipo_2 arg1,Tipo_3 arg2)
{
(*namefunction)(arg1,arg2);
}
To call it would be the following, just add a semicolon ; .
callfun(suma,3,3);