Good afternoon, I want to create in c an array of strings, where each string has 1024 characters, for this I have a variable N where it tells me the number of strings I have, I'm trying it in the following way:
char *frases[1024] = (char *) malloc(sizeof(char) * N);
But this is giving me errors.
You're doing it the other way around.
char *frases[1024]
means
an array of 1024 elements, each of which is a pointer to
char.
For such cases, I use a very simple trick : a% auxiliary% co:
struct frase_t {
char texto[1024];
};
So declaring a array of pointers of the size that we want is very simple, and I find that easier to understand:
struct frase_t *frases[N];
Now, to use struct , it must be taken into account that each element of the array must be assigned individually:
struct frase_t {
char texto[1024];
};
struct frase_t *frases[N];
for( int idx = 0; idx < N; ++idx ) {
frases[idx] = (struct frase_t *)malloc( sizeof( struct frase_t ) );
}
And that's it, an array of malloc( ) pointers, each of them points to a N , which has exactly struct frase_t 1024 .
To access any phrase any, we can do
( frases[5] )->texto
or even
(char *)( frases[5] );
Since in C, the first element of a char is guaranteed that starts at the same memory location as the struct itself.