The idea is to count the number of times a letter appears in a sentence; in this case it is b, but it gives me as a result the total of all the letters
char x='b';
String y="hola";
int n=0;
for(int i=0;i<y.length();i++) {
if(y.charAt(i)==x);
n++;
}
System.out.println(n);
}
The problem is that you have a semicolon after the if, then the counter increases with each iteration. You should do something like this:
char x='b';
String y="hola";
int n=0;
for(int i=0;i<y.length();i++) {
if(y.charAt(i)==x)
n++;
}
System.out.println(n);
Good luck!
It occurs to me that you use the indexOf() method which will return
-1 if the indicated value does not exist in the string EXAMPLE CODE
public class MyClass
{
public static void main(String arags[])
{
char x='b';
String y="hola";
if(y.indexOf(x) == -1)
{
System.out.println("La cadena no contiene el valor: "+x);
}else{
System.out.println("La cadena si contiene el valor: "+x);
}
}
}
EXPLANATION
Within the if we verify that the method indexOf() returns -1 if the element was not affirmed, it was not located and we printed a message
On the other hand, if the value does exist, we print a different message
EXAMPLE 2
If you want the code to show you the location of the character within the array, if it exists in the; then your code could look like this
public class MyClass
{
public static void main(String arags[])
{
char x='b';
String y="hola";
System.out.println(y.indexOf(x));
}
}
What you will get for output in the console is: -1 if the value does not exist or otherwise it can be:
| 0 | 1 | 2 | 3 | -> posiciones en el array
-----------------
| h | o | l | a | ->elemento por cada posición en el array