I have a question:
How can I make or modify this subprogram so that when I enter the name of the file as input parameter, give me this name.txt?
I attach the Subprogram here:
void guardar_fic(string nom_fic){
ofstream entrada;
entrada.open("nom_fic.txt");
entrada<<"EOO"<<endl;
entrada.close();
}
Pd: In the case of putting for example; guardar_fic(PEPE) create me the file as PEPE.txt
Thank you.
What I think you could do is
nom_fic += ".txt";
ofstream entrada;
entrada.open(nom_fic.c_str());
entrada<<"EOO"<<endl;
entrada.close();
Try it to see if it works for you.
See the constructors of std::ofstream :
basic_ofstream()
Create a data stream from write to file that does not point to any file.
explicit basic_ofstream(const char*, std::ios_base::openmode = ios_base::out)
Creates a write-to-file data flow that points to the file whose name is stored in the array of characters received as the first parameter.
explicit basic_ofstream(const std::filesystem::path::value_type*, std::ios_base::openmode = ios_base::out)
Create a data stream from write to file that points to the file that is in the route received as the first parameter.
explicit basic_ofstream( const std::string&, std::ios_base::openmode = ios_base::out)
Creates a data stream from write to file that points to the file whose name is stored in the string received as the first parameter.
explicit basic_ofstream( const std::filesystem::path&, std::ios_base::openmode = ios_base::out)
Create a data stream from write to file that points to the file that is in the route received as the first parameter.
So you can open a file with std::string , so your function would look like this:
void guardar_fic(std::string nom_fic){
if (std::ofstream entrada{nom_fic + ".txt"}) {
entrada << "EOO\n";
}
// No es necesario llamar a entrada.close,
// se llama automáticamente al salir del if.
}