How can I calculate the letter NIF of a DNI?

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How can I calculate the letter NIF of a DNI?

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ENUNCIADO:

The algorithm to obtain the letter of the NIF corresponding to a DNI consists of the following steps:

Obtain the rest of the entire division of the DNI by 23.
The letter is the one in the indexed position of the following string, which corresponds the value of the previous waste: "TRWAGMYFPDXBNJZSQVHLCKE" example: the remainder of divide 22334455 between 23 is 6 and in position 6 of the previous chain is found the letter Y'. (The positions of the text strings start at 0).
Make a program that asks to enter DNI numbers until the user ends by entering a specific character (f | F).
DNI s must be stored in an array that starts with size 1 and must resize, increasing it in one position each time the user enters a new DNI.
The program must show the NIFs with their letters.

ENTRY OF DNI s:

DEPARTURE OF NIF s:

After the attached statement what I have done: link

public static void main(String[] args) {

        Scanner lector = new Scanner(System.in);

        String[] letras = {"T", "R", "W", "A", "G", "M", "Y", "F", "P", "D", "X", "B", "N", "J", "Z", "S", "Q", "V", "H", "L", "C", "K", "E"};
        int[] valors = new int[5];
        int ocupacio = 0, i, x;
        int posicion;

        do {
            System.out.println("Introduce numeros de DNI");

            for (i = 0; i < valors.length; i++) {
                if (lector.hasNextInt()) {
                    valors[i] = lector.nextInt();

                } else if (lector.hasNext("fi")) {
                    break;

                } else {

                    System.out.println("Dada Incorrecta");
                    lector.nextLine();
                    i--;

                }

            }

            for (x = 0; x < letras.length; x++) {
                letras[x] = lector.next();

                ocupacio = i;
                posicion = x % 23;

                for (int j = 0; j < ocupacio; j++) {
                    System.out.println(valors[j]);

                    System.out.println("NIF: " + valors[j] + "-"+ letras[posicion]);
                }

            }

        } while (!lector.hasNext("fi"));

    }
}

I only have the last part that is to resize the array so that it shows me the letter next to the DNI that I enter and also not put together each letter with each DNI, I know that something has to be done with a counter but I do not know how do it and the truth is that I'm desperate, I hope you can give me a hand, many thanks from my heart.

java

asked by Aitor 13.02.2017 в 20:18

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2 answers

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In your exercise you had several errors of use of the Scanner class. And an important mess with the do-while and the for of its interior.

Here I leave the example that I have done using everything that is good of your code and leaving it as simple as possible

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {

        Scanner lector = new Scanner(System.in);

        String[] letras =
                          {"T", "R", "W", "A", "G", "M", "Y", "F", "P", "D", "X", "B", "N", "J", "Z", "S", "Q", "V", "H", "L", "C", "K",
                                  "E"};
        //Creamos el array con longitud 0 para ir ampliandolo como pide el enunciado.
        int[] valors = new int[0];
        int ocupacio = 0, i = 0, x;
        int posicion;
        boolean fi = false;

        System.out.println("Introduce numeros de DNI");
        do {
            if (lector.hasNextInt()) {
                int[] arrayAmpliado = new int[valors.length + 1];

                if(i > 0){
                    for (int j = 0; j < valors.length; j++) {
                        arrayAmpliado[j] = valors[j];
                    }
                }

                valors = arrayAmpliado;
                valors[i] = lector.nextInt();

            } else if (lector.hasNext()) {
                String s = lector.next();

                if ("f".equals(s) || "F".equals(s)) {
                    fi = true;
                }
            } else {

                System.out.println("Dada Incorrecta");
                lector.nextLine();
                i--;
            }

            i++;
        } while (!fi);

        for(int valor : valors){
            String letra = letras[valor % 23];

            System.out.println(valor + letra);
        }
    }
}

If you have any questions, we will comment on it!

answered by 15.02.2017 в 17:28

ng-repeat to duplicate tds update a single record with submit in index.html and function in views.py

score 1 · Accepted Answer

Handle the digits entered in an array and create an array with size plus one with each entry is not very efficient, but I guess it is a task in which you must work with primitives. Do not get used to it.

import java.io.IOException;

public class Dni {

    public static final String[] letras = {"T", "R", "W", "A", "G", "M", "Y", "F", "P", "D", "X", "B", "N", "J", "Z", "S", "Q", "V", "H", "L", "C", "K", "E"};

    int[] valors = new int[0];

    public void ingreso() throws IOException{
        System.out.println("Introduce numeros de DNI");
        int indice=0;
        int consola;
        do{
            consola = System.in.read();
            // char ingresado es [0-9]
            if (consola >=48 && consola<=57){
                // crecer arreglo, agrega digito a arreglo y incrementa indice
                valors = crecerArreglo(valors);
                valors[indice++]=consola;
            }
            // 70 y 102 son [fF]
        } while(consola !=70 && consola !=102);
        String dni = arregloToString(valors);
        int nif = Integer.valueOf(dni)%23;
        System.out.println("Resultado:");
        System.out.println(dni.concat(letras[nif]));
    }

    private int[] crecerArreglo(int[] arreglo){
        int[] remplazo = new int[arreglo.length+1];
        // copiar arreglo
        for (int i = 0; i<arreglo.length; i++) remplazo[i]=arreglo[i];
        return remplazo;
    }

    private String arregloToString(int[] arreglo){
        char[] c = new char[arreglo.length];
        for (int i =0; i<arreglo.length;i++){
            c[i]=(char) (arreglo[i]);
        }
        return new String(c);
    }

    public static void main(String[] args) {
        Dni dni=new Dni();
        try {
            dni.ingreso();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

}